JEE Main Maths · Complex Numbers PYQ

JEE Main Complex Numbers Previous Year Questions (2002–2025)

Complex Numbers is a P1 Algebra foundation chapter — ~5% JEE Main weightage with 1–2 questions per session. Mastery here supports Quadratic Equations (complex roots), Trigonometry (De Moivre's) and Coordinate Geometry (Argand plane). High-yield chapter for dedicated Algebra students.

Complex Numbers PYQs from 2002 to 2025, tagged by sub-topic (modulus/argument, De Moivre's, nth roots of unity, geometry). Every solution shows z = a + bi decomposition and trigonometric form conversions.

Complex Numbers at a Glance

Weightage
~5%
approx · 10-yr avg
Priority
P1
Must master
Year range
2002–2025
PYQ coverage
Typical in paper
1–2
per session

Key Sub-Topics & What's Tested

Complex Number Basics

z = a + bi, real/imaginary parts, conjugate z̄ = a - bi, addition, multiplication, division.

Modulus & Argument

|z| = √(a² + b²), arg(z) ∈ (-π, π], polar form z = r(cos θ + i sin θ), relationship |z₁ z₂| = |z₁||z₂|.

Argand Plane

Geometric representation of complex numbers, rotation by θ = multiplication by cis θ, distance between two complex numbers.

De Moivre's Theorem

(cos θ + i sin θ)^n = cos nθ + i sin nθ, applications to trigonometric identities, nth roots of complex number.

Nth Roots of Unity

Solutions of zⁿ = 1: ω = e^(2πi/n), cube roots of unity (1, ω, ω²), properties 1 + ω + ω² = 0, ω³ = 1.

Geometric Interpretation

|z - a| = r is circle, |z - a| + |z - b| = 2k is ellipse (for 2k > |a - b|), arg((z-a)/(z-b)) = const is arc.

Complex Conjugate Properties

z + z̄ = 2 Re(z), z - z̄ = 2i Im(z), z·z̄ = |z|², conjugate of sum = sum of conjugates.

Triangle Inequality

||z₁| - |z₂|| ≤ |z₁ ± z₂| ≤ |z₁| + |z₂|, equality conditions, applications in range problems.

Question Type Distribution

Question TypeShare (approx)Example Pattern
Modulus / Argument Calculation25%Find |1 + i|^n where n = 10.
Nth Roots of Unity Problem20%If ω is cube root of unity, evaluate 1 + ω + ω² and 1 + ω² + ω⁴.
Geometric Locus15%|z - 2| + |z + 2| = 10 represents which conic?
De Moivre's Application15%Evaluate (1 + i)^8 using De Moivre's theorem.
Complex Equation Solving15%Find all z satisfying z² + |z| = 0.
Conjugate / Triangle Inequality10%Prove that |z₁ + z₂|² + |z₁ - z₂|² = 2(|z₁|² + |z₂|²).

How to Solve Complex Numbers PYQs

  1. 1
    Convert to polar form for De Moivre. z = r·cis θ where cis θ = cos θ + i sin θ. Powers and roots become rotations in polar form — much faster than Cartesian.
  2. 2
    Memorise cube roots of unity properties. 1 + ω + ω² = 0, ω³ = 1, ω·ω̄ = 1, ω̄ = ω². These identities appear frequently across PYQs.
  3. 3
    For geometric locus, interpret |z - a| and arg. |z - a| = r → circle radius r centre a. |z - a| - |z - b| = const → hyperbola. arg((z-a)/(z-b)) = const → arc.
  4. 4
    Use conjugate for real/imaginary extraction. Re(z) = (z + z̄)/2, Im(z) = (z - z̄)/(2i). Useful when separating real and imaginary parts in equations.
  5. 5
    Nth roots of unity lie on unit circle. They are evenly spaced around |z| = 1. Sum of all n roots = 0 for n ≥ 2. Key property.

Common Mistakes That Cost Marks

  • Wrong sign for conjugate. z̄ = a - bi (flips sign of imaginary part only). Not -a - bi.
  • Missing periodicity of argument. arg(z) is defined modulo 2π. Principal value is in (-π, π]. Ignoring this gives ambiguous answers.
  • Applying De Moivre's to r^n incorrectly. (r·cis θ)^n = rⁿ·cis(nθ). Both magnitude AND angle change.
  • Using ω² as ω instead of conjugate. For cube roots, ω² = ω̄ (complex conjugate). Confusing these breaks identity calculations.
  • Wrong triangle inequality direction. |z₁ + z₂| ≤ |z₁| + |z₂| (sum). |z₁ - z₂| ≥ ||z₁| - |z₂|| (difference). Don't confuse.

Frequently asked questions

How many Complex Numbers PYQs should I solve?

Target 60–80 PYQs across 2010–2025. Given the chapter's role as foundation for multiple downstream topics, consistent practice has compound returns.

Is De Moivre's theorem tested every year?

Yes — at least one PYQ per paper uses De Moivre's theorem directly or implicitly (via polar form of complex powers/roots). Mastering it is non-negotiable.

What's the most-tested Complex Numbers pattern?

Cube roots of unity identities (1 + ω + ω² = 0, ω³ = 1) — appears in ~5 PYQs per 10-year window in different disguises.

Do I need hyperbolic identities for Complex Numbers?

No — JEE Main stays within standard trigonometric (cos, sin) and exponential complex identities. Hyperbolic functions are beyond the syllabus here.

How should I approach geometric locus PYQs?

Let z = x + iy. Translate condition to x, y equation. Recognise standard conic form (circle, ellipse, parabola, hyperbola). Many PYQs are disguised conic-section problems.

Does Complex Numbers connect with Quadratic Equations?

Yes — quadratic equations with negative discriminant have complex roots. PYQs test this link via problems asking for product/sum of complex roots.

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